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4x^2+2.7x-2.7=0
a = 4; b = 2.7; c = -2.7;
Δ = b2-4ac
Δ = 2.72-4·4·(-2.7)
Δ = 50.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.7)-\sqrt{50.49}}{2*4}=\frac{-2.7-\sqrt{50.49}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.7)+\sqrt{50.49}}{2*4}=\frac{-2.7+\sqrt{50.49}}{8} $
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